0=2x^2-x+4

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Solution for 0=2x^2-x+4 equation:



0=2x^2-x+4
We move all terms to the left:
0-(2x^2-x+4)=0
We add all the numbers together, and all the variables
-(2x^2-x+4)=0
We get rid of parentheses
-2x^2+x-4=0
a = -2; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-2)·(-4)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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